# Heat Transfer by Conduction through a Cylindrical Wall

Written by Jerry Ratzlaff on . Posted in Thermodynamics

This calculation determines the heat transfer through a cylinder wall by conduction

 $$\large{ Q_c = \frac { 2 \; \pi \; k \; l \; \left( T_1 \;-\; T_2 \right) } { ln \; \left( \frac {r_2 }{ r_1 } \right) } }$$ Where: $$\large{ Q_c }$$ = heat transfer by conduction $$\large{ l }$$ = length of material $$\large{ r_1 }$$ = radius inside diameter (ID) $$\large{ r_2 }$$ = radius outside diameter (OD) $$\large{ T_1 }$$ = temperature of one surface of the wall $$\large{ T_2 }$$ = temperature of the other surface of the wall $$\large{ k }$$ = thermal conductivity